HandyJSON

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Swift语言JSON转Model工具库

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HandyJSON

HandyJSON is a framework written in Swift which to make converting model objects(classes/structs) to and from JSON easy on iOS.

Compared with others, the most significant feature of HandyJSON is that it does not require the objects inherit from NSObject(not using KVC but reflection), neither implements a 'mapping' function(use pointer to achieve property assignment).

Build Status
Carthage compatible
Cocoapods Version
Cocoapods Platform
Codecov branch

中文文档

Sample Code

Deserialization

class Animal: HandyJSON {
    var name: String?
    var height: Double?

    init() {}
}

let json = "{\"name\": \"Tom\", \"height\": 25.0}"

if let cat = JSONDeserializer<Animal>.deserializeFrom(json: json) {
    print(cat)
}

Serialization

class Animal {
    var name: String?
    var height: Double?

    init(name: String, height: Double) {
        self.name = name
        self.height = height
    }
}

let cat = Animal(name: "cat", height: 25.0)

print(JSONSerializer.serialize(model: cat).toJSON()!)
print(JSONSerializer.serialize(model: cat).toPrettifyJSON()!)
print(JSONSerializer.serialize(model: cat).toSimpleDictionary()!)

Content

Features

  • Serialize/Deserialize Object/JSON to/From JSON/Object

  • Naturally use object property name for mapping, no need to specify a mapping relationship

  • Support almost all types in Swift

  • Support struct

  • Custom transformations for mapping

  • Type-Adaption, such as string json field maps to int property, int json field maps to string property

Requirements

  • iOS 8.0+/OSX 10.9+/watchOS 2.0+/tvOS 9.0+

  • Swift 2.3+ / Swift 3.0+

Installation

To use with Swift 2.x using == 0.4.0

To use with Swift 3.x using >= 1.2.1

For Legacy Swift support, take a look at the swift2 branch.

Cocoapods

Add the following line to your Podfile:

pod 'HandyJSON', '~> 1.2.1'

Then, run the following command:

$ pod install

Carthage

You can add a dependency on HandyJSON by adding the following line to your Cartfile:

github "alibaba/HandyJSON" ~> 1.2.1

Manually

You can integrate HandyJSON into your project manually by doing the following steps:

  • Open up Terminal, cd into your top-level project directory, and add HandyJSON as a submodule:
git init && git submodule add https://github.com/alibaba/HandyJSON.git
  • Open the new HandyJSON folder, drag the HandyJSON.xcodeproj into the Project Navigator of your project.

  • Select your application project in the Project Navigator, open the General panel in the right window.

  • Click on the + button under the Embedded Binaries section.

  • You will see two different HandyJSON.xcodeproj folders each with four different versions of the HandyJSON.framework nested inside a Products folder.

    It does not matter which Products folder you choose from, but it does matter which HandyJSON.framework you choose.

  • Select one of the four HandyJSON.framework which matches the platform your Application should run on.

  • Congratulations!

Deserialization

The Basics

To support deserialization from JSON, a class/struct need to conform to 'HandyJSON' protocol. It's truly protocol, not some class inherited from NSObject.

To conform to 'HandyJSON', a class need to implement an empty initializer.

class Animal: HandyJSON {
    var name: String?
    var id: String?
    var num: Int?

    required init() {}
}

let jsonString = "{\"name\":\"cat\",\"id\":\"12345\",\"num\":180}"

if let animal = JSONDeserializer<Animal>.deserializeFrom(json: jsonString) {
    print(animal)
}

Support Struct

For struct, since the compiler provide a default empty initializer, we use it for free.

struct Animal: HandyJSON {
    var name: String?
    var id: String?
    var num: Int?
}

let jsonString = "{\"name\":\"cat\",\"id\":\"12345\",\"num\":180}"

if let animal = JSONDeserializer<Animal>.deserializeFrom(json: jsonString) {
    print(animal)
}

But also notice that, if you have a designated initializer to override the default one in the struct, you should explicitly declare an empty one.

Optional, ImplicitlyUnwrappedOptional, Collections and so on

'HandyJSON' support classes/structs composed of optional, implicitlyUnwrappedOptional, array, dictionary, objective-c base type, nested type etc. properties.

class Cat: HandyJSON {
    var id: Int64!
    var name: String!
    var friend: [String]?
    var weight: Double?
    var alive: Bool = true
    var color: NSString?

    required init() {}
}

let jsonString = "{\"id\":1234567,\"name\":\"Kitty\",\"friend\":[\"Tom\",\"Jack\",\"Lily\",\"Black\"],\"weight\":15.34,\"alive\":false,\"color\":\"white\"}"

if let cat = JSONDeserializer<Cat>.deserializeFrom(json: jsonString) {
    print(cat)
}

Designated Path

HandyJSON supports deserialization from designated path of JSON.

class Cat: HandyJSON {
    var id: Int64!
    var name: String!

    required init() {}
}

let jsonString = "{\"code\":200,\"msg\":\"success\",\"data\":{\"cat\":{\"id\":12345,\"name\":\"Kitty\"}}}"

if let cat = JSONDeserializer<Cat>.deserializeFrom(json: jsonString, designatedPath: "data.cat") {
    print(cat.name)
}

Composition Object

Notice that all the properties of a class/struct need to deserialized should be type conformed to HandyJSON.

class Component: HandyJSON {
    var aInt: Int?
    var aString: String?

    required init() {}
}

class Composition: HandyJSON {
    var aInt: Int?
    var comp1: Component?
    var comp2: Component?

    required init() {}
}

let jsonString = "{\"num\":12345,\"comp1\":{\"aInt\":1,\"aString\":\"aaaaa\"},\"comp2\":{\"aInt\":2,\"aString\":\"bbbbb\"}}"

if let composition = JSONDeserializer<Composition>.deserializeFrom(json: jsonString) {
    print(composition)
}

Inheritance Object

A subclass need deserialization, it's superclass need to conform to HandyJSON.

class Animal: HandyJSON {
    var id: Int?
    var color: String?

    required init() {}
}


class Cat: Animal {
    var name: String?

    required init() {}
}

let jsonString = "{\"id\":12345,\"color\":\"black\",\"name\":\"cat\"}"

if let cat = JSONDeserializer<Cat>.deserializeFrom(json: jsonString) {
    print(cat)
}

Array In JSON

If the first level of a JSON text is an array, we turn it to objects array.

class Cat: HandyJSON {
    var name: String?
    var id: String?

    required init() {}
}

let jsonArrayString: String? = "[{\"name\":\"Bob\",\"id\":\"1\"}, {\"name\":\"Lily\",\"id\":\"2\"}, {\"name\":\"Lucy\",\"id\":\"3\"}]"
if let cats = JSONDeserializer<Cat>.deserializeModelArrayFrom(json: jsonArrayString) {
    cats.forEach({ (cat) in
        if let _cat = cat {
            print(_cat.id ?? "", _cat.name ?? "")
        }
    })
}

Custom Mapping

HandyJSON let you customize the key mapping to JSON fields, or parsing method of any property. All you need to do is implementing an optional mapping function, do things in it.

class Cat: HandyJSON {
    var id: Int64!
    var name: String!
    var parent: (String, String)?

    required init() {}

    func mapping(mapper: HelpingMapper) {
        // specify 'cat_id' field in json map to 'id' property in object
        mapper.specify(property: &id, name: "cat_id")

        // specify 'parent' field in json parse as following to 'parent' property in object
        mapper.specify(property: &parent, converter: { (rawString) -> (String, String) in
            let parentNames = rawString.characters.split{$0 == "/"}.map(String.init)
            return (parentNames[0], parentNames[1])
        })
    }
}

let jsonString = "{\"cat_id\":12345,\"name\":\"Kitty\",\"parent\":\"Tom/Lily\"}"

if let cat = JSONDeserializer<Cat>.deserializeFrom(json: jsonString) {
    print(cat)
}

Supported Property Type

  • Int/Bool/Double/Float/String/NSNumber/NSString

  • NSArray/NSDictionary

  • Int8/Int16/Int32/Int64/UInt8/UInt16/UInt23/UInt64

  • Optional<T>/ImplicitUnwrappedOptional<T> // T is one of the above types

  • Array<T> // T is one of the above types

  • Dictionary<String, T> // T is one of the above types

  • Nested of aboves

Serialization

The Basics

You need to do nothing special to support serialization. Define the class/struct, get the instances, then serialize it to json text, or simple dictionary.

class Animal {
    var name: String?
    var height: Int?

    init(name: String, height: Int) {
        self.name = name
        self.height = height
    }
}

let cat = Animal(name: "cat", height: 30)
if let jsonStr = JSONSerializer.serialize(model: cat).toJSON() {
    print("simple json string: ", jsonStr)
}
if let prettifyJSON = JSONSerializer.serialize(model: cat).toPrettifyJSON() {
    print("prettify json string: ", prettifyJSON)
}
if let dict = JSONSerializer.serialize(model: cat).toSimpleDictionary() {
    print("dictionary: ", dict)
}

Complex Object

Still need no extra effort.

enum Gender {
    case Male
    case Female
}

struct Subject {
    var id: Int64?
    var name: String?

    init(id: Int64, name: String) {
        self.id = id
        self.name = name
    }
}

class Student {
    var name: String?
    var gender: Gender?
    var subjects: [Subject]?
}

let student = Student()
student.name = "Jack"
student.gender = .Female
student.subjects = [Subject(id: 1, name: "math"), Subject(id: 2, name: "English"), Subject(id: 3, name: "Philosophy")]

if let jsonStr = JSONSerializer.serialize(model: student).toJSON() {
    print("simple json string: ", jsonStr)
}
if let prettifyJSON = JSONSerializer.serialize(model: student).toPrettifyJSON() {
    print("prettify json string: ", prettifyJSON)
}
if let dict = JSONSerializer.serialize(model: student).toSimpleDictionary() {
    print("dictionary: ", dict)
}

To Do

  • More testcases

  • Improve error handling

  • <del>Support non-object (such as basic type, array, dictionany) type deserializing directly</del> (will not support)

License

HandyJSON is released under the Apache License, Version 2.0. See LICENSE for details.

 
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